2025-08-25
I don’t really understand the limit.
A way to use Stolz is to take the logarithm.
logan−logan−1=loganan−1\log a_n - \log a_{n-1}= \log \frac{a_n}{a_{n-1}}. In case anan−1\frac{a_n}{a_{n-1}} has a limit, the limit of an−an−1a_n - a_{n-1} can be computed.